1.

the ratio of the number of side of 2 regular polygon is 1:2 and the ratio of there interior angle is 3:4 . find the number of side of polygon.

Answer»

\(\Rightarrow\) The ratio of the sides of two polygon is 1 : 2.

\(\Rightarrow\) Let the polygon A have n sides and polygon B have 2n sides.

\(\Rightarrow\) The sum of the interior angles of A is (n - 2) x 180º = 180ºn - 360º

\(\Rightarrow\)So each interior angle,

\(\Rightarrow\)\(\frac{180^on-360^o}{n}\) ............(1)

\(\Rightarrow\) Sum of interior angles of B is (2n - 2)×180º = 360ºn - 360º.

\(\Rightarrow\) \(\frac{360^on-360^o}{2n}\) ....................(2)

\(\Rightarrow\) Now the ratio of the interior angles of A and B.

\(\Rightarrow\) \(\frac{180^on-360^o}{n}\)\(\frac{360^on-360^o}{2n}\): : \(\frac{3}{4}\) .................[from (1) and (2)]

\(\Rightarrow\) \(\frac{360^on-720^o}{360^on-360^o}\) = \(\frac{3}{4}\)

\(\Rightarrow\) \(\frac{360^o(n-2)}{360^o(n-1)}\) = \(\frac{3}{4}\)

\(\Rightarrow\) 4n - 8 = 3n - 3

\(\therefore\) n = 5 and 2n = 10

Thus, the number of sides of each polygon is 5 and 10.



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