1.

The ratio of the number of sp, `sp^(2)`, and `sp^(3)` orbitals in the compound is `CH_(3)-CH=C=CH-C-=C-CH_(3)`A. `1:1:1`B. `2:2:1`C. `3:2:1`D. `3:3:4`

Answer» Correct Answer - D


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