1.

The ratio of the numer of moles of AgNO_(3), Pb(NO_(3))_(2) and Fe(NO_(3))_(3) required for coagulation of a difinite amount of a colloidal sol of silver iodide prepared by maxing Ag NO_(3) with excess of KI will be

Answer»

`1:2:3`
`3:2:1`
`6:3:2`
`2:3:6`

Solution :With excess of KI, colloidal particles will be `[AgI] I^(-)`
`{:([AgI]I^(-)+AgNo_(3)to AgI darr+ AgI darr + NO_(3)^(-)),("1 mol""""1 mol"):}`
`2[AgI]I^(-)+Pb(NO_(3)_(2)to AgI darr+ PbI _(2) darrNO_(3)^(-)`
`{:("2 mol","1 mol"),("1 mol", 1/2"mol"):}`
`3[AgI]I^(-)Fe(NO_(3))_(3)to 3 AgL darr+FeI _(3)darr+3NO_(3)^(-)`
`{:("3 mol", "1 mol"),("1 mol", 1/3 "mol"):}`
`therefore` MOLAR ratio required for coagulation of same
amount of `[AgI]I^(-)is 1:1/2:1/3=6:3:2.`


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