1.

The ratio of the radii of gyration of a circular disc and a circular ring of the same radii about a tangential axis perpendicular to plane of disc or ring is

Answer»

`1:2`
`sqrt(5) : sqrt(6)`
`2:3`
`(sqrt(3))/(2)`

Solution :Radius of GYRATION,`K=sqrt((I)/(m))`
`K_("DISC")=sqrt(((1)/(2)mR^(2)+mR^(2))/(m))=sqrt((3)/(2))R`
`R_("ring")=sqrt((mR^(2)+mR^(2))/(m))=sqrt(2)R`
`:. (K_("disc"))/(K_("ring"))=(sqrt(3//2))/(sqrt(2))=(sqrt(3))/(2)`.


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