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InterviewSolution
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The ratio of the speed of the electron in the first Bohr orbit of hydrogen and the speed of light is equal to (where `e, h` and `c` have their usual meanings)A. `(2pihc)/(e^(2))`B. `(e^(2)c)/(2pih)`C. ` (e^(2)h)/(2pihc)`D. `(e^(2))/(2epsi_(0)hc)` |
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Answer» Correct Answer - D Speed of electron in first orbit of hydrogen atom is given by `" " v=(e^(2))/(2epsi_(0)h)` ` :. " " (v)/(c)=(e^(2))/(2epsi_(0)hc)` |
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