1.

The ratio of the uncomplexed to the complexed Zn^(2+) ion in a solution of 10 M NH_(3) is (Given that the stability constant of [Zn(NH_(3))_(4)]^(2+) is 3xx10^(9))

Answer»

`3.3xx10^(-9)`
`3.3xx10^(-11)`
`3.3xx10^(-13)`
`3.3xx10^(-14)`

Solution :`Zn^(2+)+4NH_(3)iff[Zn(NH_(3))_(4)]^(2+)`
`K=([Zn(NH_(3))_(4)]^(2+))/([Zn^(2+)][NH_(3)]^(4))therefore 3xx10^(9)=([Zn(NH_(3))_(4)]^(2+))/([Zn^(2+)](10)^(4))`
`or ([Zn^(2+)])/([Zn(NH_(3))_(4)]^(2+))=(1)/(3xx10^(9)xx10^(4))=3.33xx10^(-14)`


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