1.

The ratio of the value of any colligative property of KCl solution to that of sugar solution is

Answer»


Solution :Van't HOFF factor (i) `=("EXP. C.P.")/("Cal. C.P.")=1-ALPHA+x alpha+y alpha` ,
For KCl it is = 2 and for sugar it is EQUAL to 1.
`therefore (C.P._(KCl))/(C.O._("Sugar"))=2`


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