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    				| 1. | The ratio of the volumes of two right circular cones is `1:4` and the ratio of their lengths of radii of the bases is `4:5` then the ratio of their heights isA. `1:5`B. `5:4`C. `25:16`D. `25:64` | 
| Answer» Let the lengths of the radii of the bases of the right circular cone area `4x` unit and `5x` unit. Also , let heights of the two right circular cones are `h_1` unit and `h_2` unit. So, the volume of the cones are `(1)/(3)pi(4x)^2h_1` cubic - units and `(1)/(3)pi(5x)^2h_2` cubic-unit. As per question, `(1)/(3)pi(4x)^2h_1:(1)/(3)(5x)^2h_2` cubic - unit. `rArr 16x^2h_1:25x^2h_2=1:4rArr (16x^2h_1)/(25x^2h_2)=(1)/(4)rArr (h_1)/(h_2)(1)/(4)xx(25)/(64)rArr h_1:h_2=25:64` Hence the ratio of the heights of the two right circularf cones is `25:64` . `therefore` (d) is correct. | |