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The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘ a ’ is `3 : 2`. The value of ‘ a ’ is ( g - Acceleration due to gravity of the earth)A. `(g)/(3)`B. `(g)/(2)`C. `g`D. `(4)/(3)g` |
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Answer» Correct Answer - A `(mg)/(m(g-a))=(3)/(2)` `2g=3(g-a)` `a=(g)/(3)` |
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