The ratio of volumes of CH_(3)C O O H, 0.1 N to CH_(3) C O O Na, 0.1 N requiredto prepare a buffer solution of pH 5.74is (given : pK_(a) of CH_(3) C O O H is 4+74 )

The ratio of volumes of CH_(3)C O O H, 0.1 N to CH_(3) C O O Na, 0.1 N

1.	The ratio of volumes of CH_(3)C O O H, 0.1 N to CH_(3) C O O Na, 0.1 N requiredto prepare a buffer solution of pH 5.74is (given : pK_(a) of CH_(3) C O O H is 4+74 )
Answer» `10:1` `5:1` `1:5` `1:10` SOLUTION :Suppose volume of 0.1 N `CH_(3)CO OH` solution = V mL and volume of 0.1 N `CH_(3)CO OnN`a solution = X V mL `CH_(3)CO OH` present in the final solution `=(0.1)/(1000)xxV ` mol = `Vxx10^(-4)` mol `CH_(3)CO ON`apresent in the final solution `=(0.1)/(1000)XX x V "mol" = x V xx 10^(-4)` mol `pH = pK_(a) + log .(["Salt"])/(["Acid"])` `:. 5.74=4.74+log. (x V xx10^(-4))/(V xx 10^(-4))` orlog x = 1or x = 10 `:. ` Ratio = V mL : x V mL = 1 : x = 1 : 10