1.

The ratio of volumes of CH_3 COOH 0.1 (N) to CH_3 COONa 0.1 (N) required to prepare a buffer solution of pH 5.74 is (given : pK_aof CH_3 COOH is 4.74)

Answer»

`10 :1`
`5 :1`
`1 :5`
`1 :10`

Solution :`pH = pK_a+log_(10)("Activityofsalt ")/("ACTIVITYOF acid ")`
` 5.74 =4.74 + log_(10) "concentration" xx "Volume "_(("SALT"))/( "concentration" xx"volume"_("acid"))`
[Concentrationgivenare same ]
` 1= log_(10)(v_("salt"))/( V_("acid ")) impliesV_("salt ") : V_("acid")= 10 :1 `
`thereforeV_("acid") :V_("salt")= 1: 10`


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