1.

The ration of mass per cent of C and H of an organic compound (C_(x)H_(y)O_(z)) "is"6:1. If one molecule of the above compound (C_(x)H_(Y)O_(z)) contains half as much oxygen as required to burn one molecule of compound C_(x)H_(Y) compleltely to CO_(2) and H_(2)O. The empirial formula of compound C_(x)H_(y)O_(z) is:

Answer»

`C_(3)H_(6)O_(3)`
`C_(2)H_(4)O`
`C_(2)H_(4)O`
`C_(3)H_(4)O_(2)`

ANSWER :A


Discussion

No Comment Found

Related InterviewSolutions