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The ration of the `e//m` (specific charge) values of an electron and an `alpha-"particle"` isA. `2:1`B. `1:1`C. `1:1`D. None of these |
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Answer» Correct Answer - D `(e/m)_e=e/m_e(e/m)_alpha=(2e)/m_alpha=(4e)/(4m_p)=(2e)/(4xx1840m_e)implies ((e//m)_e)/((e//m)_alpha)=3680` |
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