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The reactant which is entirely consumed in reaction is known as limiting reagent, in the reaction 2 A + 4 B rarr 3 C + 4D, when 5 moles of A react with 6 moles of B, then (i) which is the limiting reagent ? (ii) calculate the amount of C formed ? 2A + 4 B rarr 3 C + 4D |
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Answer» Solution :ACCORDING to the GIVEN reaction, 2 moles of A react with 4 moles of B hence, 5 moles of A will react with 10 moles of B (`(5xx4)/(2)=10` moles) (i) In the first case reactant B is limiting reagent as it will CONSUME first in reaction because we have only 6 moles of B. (ii) Limiting reagent decide the amount of product produced. According to the reaction, 4 moles of B produces 3 moles of C `:.` 6 moles of B willproduce `=(3xx6)/(4) = 4.5` moles of C. Note : Limiting reagent limits the amount of product formed because it is present in lesser amount and gets consumed first. |
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