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The reactant which is entirely consumed in reactions is known as limiting reagent. In the reaction 2A+4B rarr 3C+4D, when 5 moles of A react with 6 moles of B, then (i) which is the limiting reagent ? (ii) calculate the amount of C formed ? |
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Answer» Solution :According to the GIVEN equation, 2 moles of A react with 4 moles of B. `therefore` 5 moles of A will react with 10 moles of B, But we have only 6 moles of B. 6 moles of will react 3 moles of A and 2 moles of A will unreacted. THUS, (i) B is limiting a A is the excess reactant. (II) The AMOUNT of C formed will depend upon the limiting reactant i.e., 6 moles of B 4 moles of B FORM C = 3 moles `therefore"6 moles of B will form C"=(3)/(4)xx6="4.5 moles."` |
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