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The reactioin of HBr with `CH_(3)C-undeA. `CH_(3)underset(CH_(3))underset(|)(CBr)-CH_(3)`B. `CH_(3)CH_(2)CH_(2)CH_(2)-Br`C. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)Br`D. `CH_()CH_(2)-underset(Br)underset(|)(C)-H-CH_(3)` |
Answer» Correct Answer - C | |