1.

The reaction , 2AB(g) + 2C(g) to A_(2(g)) + 2BC_((g)) proceeds according to the mechanism . I. 2AB hArr A_(2)B_(2)(fast) II. A_(2)B_(2)+C to A_(2)B + BC(slow ) III. A_(2)B+C to A_(2)+BC (fast) what will be the initial rate taking [AB] = 0.2 M and [C] = 0.5 M ?The K_(c)for the step I is10^(2) M^(-1)and rate constant for the step II is3.0 xx 10^(-3) mol^(-1) min^(-1)

Answer»

`0.0716 M MIN^(-1)`
`0.0891 M min^(-1)`
`0.006 M min^(-1)`
`0.0257 M min^(-1)`

ANSWER :C


Discussion

No Comment Found

Related InterviewSolutions