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The reaction `_(3)^(7)Li+_(1)^(1)H rightarrow _(4)^(7)Be + _(0)^(1)n` is endothermic. Assuming that Li nuclei is free and at rest. What is the minimum kinetic energy ( in keV) of incident proton so that this reaction occurs? Take Q value of this reaction as -1645 keV. |
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Answer» Correct Answer - `1880 ke V` Energy available `=1/2mu v_(rel)^(2)=Q` value `=1/2xx(7xx1)/(7+1)xxv_(rel)^(2)=Q` value `Rightarrow 1/2xxv_(rel)^(2)=Qxx8/7` `K_(i)=1645xx8/7=1880` ke V |
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