1.

The reaction, 3Br_(2)+6CO_(3)^(2-)+3H_(2)Oto5Br^(-)+BrO_(3)^(-)+6HCO_(3)^(-)

Answer»

decolourization of reddish brown colour of `Br_(2)`
addition of `H_(2)SO_(4)` will increase INTENSITY of reddish brown colour of `Br_(2)`
bromine is REDUCED
it is disproportionation reaction or autoredox change

Solution :`3Br_(2)+6HO^(-)to5Br^(-)+BrO_(3)^(-)+3H_(2)O`,`5Br^(-)+BrO_(3)+6H^(+)to3Br_(2)+3H_(2)O`
Addition of `H_(2)SO_(4)` shift reaction in reverse direction.
So, bromine is GETTING oxidised as well as reduced.


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