1.

The reaction between N_(2) and H_(2) to from ammonia has K_(c)6xx10^(-2) at the temperaturee 500^(@)C. The numerical value of K_(p) for this reaction is

Answer»

<P>`1.5xx10^(-5)`
`1.5xx10^(5)`
`1.5xx10^(-6)`
`1.5xx10^(6)`

Solution :`K_(p)=K_(c)(RT)^(Deltan),Deltan=2-4=-2`
`K_(p)=6xx10^(-2)XX(0.0812xx773)^(-2)`
`K_(p)=(6xx10^(-2))/((0.0812xx773)^(2))=1.5xx10^(-5)`


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