The reaction CO(g) +3H_(2)(g) hArr CH_(4)(g)+H_(2)O(g) is at equilibrium at 1300 K in a 1K flask. It also contain 0.30 mol of CO, 0.10 mol of H_2 and 0.02 mol of H_2O and unknown amount of CH_(4) in the flask. Determine the cocentration of CH_(4) in the mixture . The equilbrium constant, K_C for the reaction at the given temperature is 3.90.

The reaction CO(g) +3H_(2)(g) hArr CH_(4)(g)+H_(2)O(g) is at equilibri

1.	The reaction CO(g) +3H_(2)(g) hArr CH_(4)(g)+H_(2)O(g) is at equilibrium at 1300 K in a 1K flask. It also contain 0.30 mol of CO, 0.10 mol of H_2 and 0.02 mol of H_2O and unknown amount of CH_(4) in the flask. Determine the cocentration of CH_(4) in the mixture . The equilbrium constant, K_C for the reaction at the given temperature is 3.90.
Answer» Solution :`CO(G)+ 3H_(2)(g) HARR CH_(4) (g) +H_(2)O(g)` `K_(c)=([CH_4]xx[H_2O])/([CO] xx [H_2]^3)or 3.90 = ([CH_4]xx[0.02])/([0.30] xx[0.1]^3)` `[CH_4] = ((3.9)xx(0.30) xx (0.001))/((0.0.2 ))=5.85 xx 10^(-2) M`