The reaction is CH_(2) = CH- CH_(3) + HBr rarr CH_(3) - CHBr-CH_(3)

1.	The reaction is CH_(2) = CH- CH_(3) + HBr rarr CH_(3) - CHBr-CH_(3)
Answer» NUCLEOPHILIC addition Electrophilic substitution Electrophilic addition Free RADICAL addition Answer :C

Discussion