1.

The reaction is of 1^(st) order.At initial the concentration of reactant is 0.1 mol L^(1) .Rate constant is =3xx10^(-2)s^(-1).Then what is the rate of reaction at initial?

Answer»

`3xx10^(-3)` MOL `L^(-1)s^(-1)`
`2XX10^(-3)` mol `L^(-1)s^(-1)`
`1xx10^(-3)` mol`L^(-1)s^(-1)`
`0.1xx10^(-3)` mol `L^(-1)s^(-1)`

SOLUTION :Rate=k`[R]^(1)`
`=(3xx10^(-2)L^(1)s^(-1))`(0.1 mol `L^(-1)`)
`=3xx10^(-3) "mol" L^(-1) s^(-1)`


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