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The reaction of `C_(6) H_(5) CH=CHCH_(3)` with HBr produces :A. `C_(6)H_(5)- underset(Br) underset(|)(CH)CH_(2)-CH_(3)`B. `C_(6)H_(5)-CH_(2) - underset (B) underset(|) (CH)CH_(3)`C. `C_(6)H_(5)-CH_(2)-CH_(2)-CH_(2)-Br`D. |
Answer» Correct Answer - A | |