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The reaction of `C_(6) H_(5) CH=CHCH_(3)` with HBr produces :A. `C_(6)H_(5)CH_(2)CH_(2)CH_(2)Br`B. `C_(6)H_(5)CH_(2)-underset(Br)underset(|)(CHCH_(3))`C. `C_(6)H_(5)-underset(Br)underset(|)(CHCH_(2))CH_(3)`D. `p-Br -C_(6)H_(4)-CH=CHCH_(3)`

Answer» Correct Answer - C


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