The reaction of Cl_(2) gas with cold-dilute and hot-concentrated NaOH in water give sodium salts to two (different) oxoacids of chlorine, P and Q, respectively. The Cl_(2) gas reacts with SO_(2) gas, in presence of charcoal, to give a product R. R reacts with white phosphours to give a compound S. On hydrolysis. S gives an oxoacid of phosphorus T. Q. R, S and T, respectively

The reaction of Cl_(2) gas with cold-dilute and hot-concentrated NaOH

1.	The reaction of Cl_(2) gas with cold-dilute and hot-concentrated NaOH in water give sodium salts to two (different) oxoacids of chlorine, P and Q, respectively. The Cl_(2) gas reacts with SO_(2) gas, in presence of charcoal, to give a product R. R reacts with white phosphours to give a compound S. On hydrolysis. S gives an oxoacid of phosphorus T. Q. R, S and T, respectively
Answer» `SO_(2)Cl_(2),PCl_(5) & H_(3)PO_(4)` `SO_(2)Cl_(2),PCl_(3)&H_(3)PO_(3)` `SOCl_(2),PCl_(3)&H_(3)PO_(2)` `SOCl_(2),PCl_(5)&H_(3)PO_(4)` Solution :(a) `Cl_(2)+"cold DIL. "NaOHtoNaOCl+NaCl` `Cl_(2)+"hot conc. "NaOHtoNaClO_(3)+NaCl` NaOCl is salt of hypochlorous acid=F `NaOCl_(3)` is salt of chloric acid=Q. `Cl_(2)+SO_(2) overset("CHARCOAL")toSO_(2)Cl_(2)(R)` `PCl_(5)+H_(2)O to H_(3)PO_(4)(T)+HCL`