1.

The reaction of cyanamlde, NH_(2) CN_((s)), with dioxygen was carried out in a bomb calorimeter, and DeltaU was found to be -742.7 "kJ mol"^(-1) at 298 K. Calculate enthalpy change for the reaction at 298 K. NH_(2) CN_((g)) + (3)/(2) O_(2(g)) to N_(2(g)) + CO_(2(g)) + H_(2) O_((l))

Answer»

SOLUTION :`Deltan_((G)) = n_(p) - n_(R)`
`=2-(3)/(2) = +(1)/(2) "mol"`
`Deltan_((g)) = Delta U + Deltan_((g)) "RT"`
`= -742.7 + (+(1)/(2) ) (8.314 xx 10^(-3) ) (298)`
`= -742.7 + 1.2`
`= -741.5 "kJ mol"`


Discussion

No Comment Found