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The reaction of cyanamlde, NH_(2) CN_((s)), with dioxygen was carried out in a bomb calorimeter, and DeltaU was found to be -742.7 "kJ mol"^(-1) at 298 K. Calculate enthalpy change for the reaction at 298 K. NH_(2) CN_((g)) + (3)/(2) O_(2(g)) to N_(2(g)) + CO_(2(g)) + H_(2) O_((l)) |
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Answer» SOLUTION :`Deltan_((G)) = n_(p) - n_(R)` `=2-(3)/(2) = +(1)/(2) "mol"` `Deltan_((g)) = Delta U + Deltan_((g)) "RT"` `= -742.7 + (+(1)/(2) ) (8.314 xx 10^(-3) ) (298)` `= -742.7 + 1.2` `= -741.5 "kJ mol"` |
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