The reaction of cynamide, NH_(2)CN(s), with dioxygen was carriedout in a bomb calorimeter, and DeltaU was found to be - 742.7 k J mol^(-1) at 298 K. Calculate the enthalpy change of the reaction at 298 K NH_(2)CN(s) + (3)/(2)O_(2)(g)rarrN_(2)(g)+CO_(2)(g) +H_(2)O(l)

The reaction of cynamide, NH_(2)CN(s), with dioxygen was carriedout in

1.	The reaction of cynamide, NH_(2)CN(s), with dioxygen was carriedout in a bomb calorimeter, and DeltaU was found to be - 742.7 k J mol^(-1) at 298 K. Calculate the enthalpy change of the reaction at 298 K NH_(2)CN(s) + (3)/(2)O_(2)(g)rarrN_(2)(g)+CO_(2)(g) +H_(2)O(l)
Answer» <P> Solution :`Deltan_(g)=(n_(p) -n_(p))_(g)= 2-(3)/(2) = +(1)/(2)` mol `DeltaH =DeltaU +Deltan_(g) RT= - 742.7 KJ mol^(-1) +(+(1)/(2)mol)(8.314xx10^(-3)kJ K^(-1) mol^(-1))(298K)` `= - 742.7 +1.2kJ mol^(-1) = - 741.5 kJ mol^(-1)`