The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. Which statements is correct for given values of teh reactions.?

The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(

1.	The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. Which statements is correct for given values of teh reactions.?
Answer» Dissociation of `N_(2)O_(4)` occurs with degree of dissociation of `N_(2)O_(4) 0.35` Formation of `NO_(2)` occurs and TOTAL moles of `NO_(2)` at equilibrium `1.35` Dissociation of `N_(2)O_(4)` occurs leaving `0.35` moles at equilibrium Formation of `NO_(2)` occurs with total moles at equilibrium `2.70` SOLUTION :`underset(1)(2NO_(2)) hArr underset(N_(2)O_(4))` Total moles TAKEN `=2`, `:. P=2xx0.0821xx400=65.7 atm` Given equilibrium pressure is `77` atm, thus reaction should SHOW the CHANGE where total number of moles increases i.e., dissociation of `N_(2)O_(4)`. `{:(N_(2)O_(4),hArr,2NO_(2)),(1,,1),(1-x,,1+2x):}` Total moles at eq.=`2+x` `=(PV)/(RT)=(77xx1)/(0.0821xx400)=2.35` `:. x=0.35`