The reaction of one equivalent of HBr with CH_2=CH-CH_2-C-=CH gives :

1.	The reaction of one equivalent of HBr with CH_2=CH-CH_2-C-=CH gives :
Answer» `CH_2=CH-CH_2-C-=CBr`<BR>`CH_2=CH-CH_2-undersetunderset(Br)(\|)C=CH_2` `CH_3-undersetunderset(Br)(\|)CH-CH_2-C-=CH` `CH_2=CH-CH_2-CH=CHBr` ANSWER :C

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