1.

The reaction of propene with HOCl(Cl_(2)+H_(2)O) proceeds through the intermediate :

Answer»

`CH_(3)-CHCl-CH_(2)^(+)`
`CH_(3)-CH^(+) -CH_(2)-OH`
`CH_(3)-CH^(+)-CH_(2)-CL`
`CH_(3)-CH(OH)-CH_(2)^(+)`

SOLUTION :


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