1.

The reaction takes place in two steps as `(i) NO_(2) Cl _((g)) overset(K_(1)) to NO_(2(g)) +Cl_((g))` `(ii ) NO_(2) Cl_((g)) +Cl_((g)) overset(K_(2)) to NO_(2(g)) +Cl_(2(g))` Identify the reaction intermediate .A. `NO_(2)Cl`(g)B. `NO_(2)`(g)C. `Cl_(2)(g)`D. Cl(g)

Answer» Correct Answer - D
`NO_(2)Cl(g) overset(K_(1))to NO_(2)(g) + Cl_(g)`(free radical)
`NO_(2)Cl(g) + Cl(g) overset(K_(2))to NO_(2)(g) + Cl_(2)(g)` (The intermediate generated is Cl)


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