The reaction taking place in the cell `Pg|H_(2)(g)|HCl(1.0M)|AgCl|Ag` is 1 atmA. `AgCl+(1//2)H_(2)toAg+H^(+)+Cl^(-)`B. `Ag+H^(+)+Cl^(-)toAgCl+(1//2)H_(2)`C. `2Ag^(+)+H_(2)to2Ag+2H^(+)`D. `2Ag+2H^(+)to2Ag^(+)+H_(2)`.

The reaction taking place in the cell `Pg|H_(2)(g)|HCl(1.0M)|AgCl|Ag`

1.	The reaction taking place in the cell `Pg\|H_(2)(g)\|HCl(1.0M)\|AgCl\|Ag` is 1 atmA. `AgCl+(1//2)H_(2)toAg+H^(+)+Cl^(-)`B. `Ag+H^(+)+Cl^(-)toAgCl+(1//2)H_(2)`C. `2Ag^(+)+H_(2)to2Ag+2H^(+)`D. `2Ag+2H^(+)to2Ag^(+)+H_(2)`.
Answer» Correct Answer - A LHS electrode (oxidation half reaction) `(1)/(2)H_(2)toH^(+)+e^(-)` RHS electroe (reduction half reaction) `AgCl+e^(-)toAg+Cl^(-)` Adding the two half ractions, we get `AgCl+e^(-)toAg+H^(+)+Cl^(-)`

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The reaction taking place in the cell `Pg|H_(2)(g)|HCl(1.0M)|AgCl|Ag` is 1 atmA. `AgCl+(1//2)H_(2)toAg+H^(+)+Cl^(-)`B. `Ag+H^(+)+Cl^(-)toAgCl+(1//2)H_(2)`C. `2Ag^(+)+H_(2)to2Ag+2H^(+)`D. `2Ag+2H^(+)to2Ag^(+)+H_(2)`.

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