The reactions of Cl_(2) gas with cold dilute and hot concentrated NaOH in water give sodium salt of two (different) oxoacids of chlorine P and Q, respectively. The Cl_(2) gas reacts with SO_(2) gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, T. R, S and T, respectively are

The reactions of Cl_(2) gas with cold dilute and hot concentrated NaOH

1.	The reactions of Cl_(2) gas with cold dilute and hot concentrated NaOH in water give sodium salt of two (different) oxoacids of chlorine P and Q, respectively. The Cl_(2) gas reacts with SO_(2) gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, T. R, S and T, respectively are
Answer» <P>`SO_(2)Cl_(2), PCl_(5) and H_(3)PO_(4)` `SO_(2)Cl_(2), PCl_(3) and H_(3)PO_(3)` `SOCl_(2), PCl_(5) and H_(3)PO_(2)` `SOCl_(2), PCl_(5) and H_(3)PO_(4)` Solution :`{:(Cl_(2)+SO_(2)overset("charcoal")rarr UNDERSET("Sulphuryl CHLORIDE (R)")(SO_(2)Cl_(2))),(10 SO_(2)Cl_(2)+P_(4) rarr 10 SO_(2)+4PCl_(5)(S)),(underset((S))(PCl_(5))+4H_(2)O rarr 5 HCl + underset("Orthophosphoric ACID (T)")(H_(3)PO_(4))):}` Thus, R, S, and T are respectively `SO_(2)Cl_(2), PCl_(5) and H_(3)PO_(4)` and hence OPTION (a) is correct.