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The reading of pressure meter attached with a closed pipe is 5 xx 10^(5) Nm^(-2). On opening the valve of the pipe, the reading of the pressure meter is 4.5 xx 10^(5) Nm^(-2). Calculate the speed of the water flowing in the pipe.

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> Bernoulli.s equation <br/> ` P_1 + <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/2 <a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a> V_(I )^(2)= P_2+ 1/21/2rho V_(2) ^(2)`<br/> ` 1/2 rho( v_(2) ^(2)- V_(1) ^(2)) = P_1 -P_2` <br/>Here initial velocity `V_1= <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>` and density of water ` rho= 1000 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> m^(-3)` <br/>`1/2 xx 10 ^(3)xx V_(2) ^(2)= ( 5-4.5 ) xx 10^(5)` <br/> `V_(2)^(2) = ( 0.5 xx 10 ^(5) xx 2 )/( 10 ^(3) = 1 xx 10 ^2` <br/> ` V_(2)^(2)= ( 0.5xx 10^(5) xx 2 )/( 10^3) = 1 xx 10^2 `<br/>`V_(2)^(2) = 100` <br/> ` V_2 = 10 ms^(-1)`</body></html>


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