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The readings corresponding to the ice point and steam point for a constant pressure gas thermometer are 500 cc, and 545 cc. If the reading corresponding to room temperature be 510 cc, find the room temperature. |
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Answer» Solution :GIVEN : `V_(0) ` = 500 CC , `V_(100)` = 554cc.and `V_(t)` = 510 cc. USING , t = `[ (V_(t) - V_(0))/(V_(100) - V_(0)) ] xx 100^(@)` C ` t = [ (510 - 500)/(545 - 500) ] 100^(@) C = 22.22^(@)` C |
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