1.

The Rectangle Box With Square Base Is Open At The Top. The Maximum Volume Of The Box Made From 1200 M2 Tin,in M3 Is?

Answer»

LET the length be X and the BREADTH be y.

Now since it has a square base;

x=y

Now the surface area can be given as S= x^2+4xy (Area of square base + Area of Sides)

And Volume can be given as V = x^2y

ATQ, S=1200,so 1200=X2+4xy

y=(1200-x2)/4x

Now for V to be MAX

V'=0

V'(x)=x2y

Solving for x we GET x=20

Now y=20m

Hence volume is 20x20x10=4000 m3

Let the length be x and the breadth be y.

Now since it has a square base;

x=y

Now the surface area can be given as S= x^2+4xy (Area of square base + Area of Sides)

And Volume can be given as V = x^2y

ATQ, S=1200,so 1200=X2+4xy

y=(1200-x2)/4x

Now for V to be max

V'=0

V'(x)=x2y

Solving for x we get x=20

Now y=20m

Hence volume is 20x20x10=4000 m3


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