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The refracting angle of a prism is A and refractive index of the material of prism is `cot(A//2)` . The angle of minimum deviation will beA. `-180cm-3A`B. `-180cm-2A`C. `-90cm-2A`D. `-180cm+2A` |
Answer» Correct Answer - B (b) Refractive index,`mu=sin((A+D_(m))/2)/(sin""A/2)` `rArrcot""A/2=sin((A+D_(m))/2)/(sin""A/2)` `rArr(cot""A/2)/(sin""A/2)=sin((A+D_(m))/2)/(sin""A/2)` `sin((pi)/2-A/2)=sin((A+D_(m))/2)` `pi/2-A/2=A/2+(D_(m))/2` `rArrD_(m)=pi-2A` Angle of minimum deviation, `D_(m)=180^(@)-2A` |
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