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InterviewSolution
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The refracting angle of a prism is A and refractive index of the material of prism is `cot(A//2)` . The angle of minimum deviation will be |
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Answer» The refractive index (`mu`) of a prism of angle A and minimum deviation, `delta_(m)` is given by `mu=sin((4+delta_(m))/2)/sin(A//2)` Given, `mu=cos""A/2` `therefore cot""A/2=sin((A+delta_(m))/2)/sin(A//2)` `(cosA//2)/(sinA//2)=(sin""((A+delta))/2)/sin(A//2)rArrcos""A/2=sin((A+delta_(m))/2)` `therefore sin(90^(@)-A/2)=sin((A+delta_(m))/2)` `rArr90^(@)-A/2=(A+delta_(m))/2rArr180^(@)-A=A+delta_(m)` `rArr` Angle of minimum deviation, `delta_(m)=180^(@)-2A=pi-2A` |
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