1.

The refractive index `mu` of a medium is found to vary with wavelength `lambda` as `mu = A +(B)/(lambda^2).` What are the dimensions of A and B?

Answer» mu = `("velocity of light in vacuum")/("velocity of light in medium")`
`= "dimensionless number" `
A`mu = A +(B)/(lambda^2),therefore`, A must be
dimensionless, and `B = mu lambda^2 = [L^2]`


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