1.

The refractive index of water with respect to air, for light of wavelength Aa in air, is 4/3. What is the wavelength of the light in water?

Answer»

dnw = \(\cfrac{v_a}{v_w}\) = \(\cfrac{vλ_a}{vλ_w}\) 

\(\frac43\) gives \(\lambda_w\) = \(\frac34\lambda_a\)

= 0.75 \(\lambda_a\)

as the wavelength of the light in water.



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