The relation between faraday constant `(F)`, chemical equicalent `(E)` and electrochemical equivalent `(Z)` isA. `F = EZ`B. `F=(Z)/(E )`C. `F=(E )/(Z)`D. `F=(E )/(Z^(2))`

The relation between faraday constant `(F)`, chemical equicalent `(E)`

1.	The relation between faraday constant `(F)`, chemical equicalent `(E)` and electrochemical equivalent `(Z)` isA. `F = EZ`B. `F=(Z)/(E )`C. `F=(E )/(Z)`D. `F=(E )/(Z^(2))`
Answer» Correct Answer - C

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The relation between faraday constant `(F)`, chemical equicalent `(E)` and electrochemical equivalent `(Z)` isA. `F = EZ`B. `F=(Z)/(E )`C. `F=(E )/(Z)`D. `F=(E )/(Z^(2))`

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