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The relation between `I_(4,2)` and `I_(4,4)` isA. `I_(4,2)=1/3(sin^(5)xcos^(3)x+8I_(4,4))`B. `I_(4,2)=1/3(-sin^(5)xcos^(3)x+8I_(4,4))`C. `I_(4,2)=1/3(sin^(5)xcos^(3)x-8I_(4,4))`D. `I_(4,2)=1/3(sini^(5)xcos^(3)x+6I_(4,4))` |
Answer» Correct Answer - B | |