The relation between K_(p) and K_(c) is K_(p)=K_(c)(RT)^(Deltan) unit of K_(p)=(atm)^(Deltan), unit of K_(c)=(mol L^(-1))^(Deltan) Consider the two reaction: XeF_(6)(g)+H_(2)O(g) hArr XeO_(3)F_(4)(g)+2HF(g), K_(1) XeO_(4)(g)+XeF_(6)(g) hArr XeOF_(4)(g)+XeO_(3)F_(2)(g), K_(2) Then the equilibrium constant for the following reaction XeO_(4)(g)+2HF(g) hArr XeO_(3)F_(2)(g) is given by:

The relation between K_(p) and K_(c) is K_(p)=K_(c)(RT)^(Deltan) unit

1.	The relation between K_(p) and K_(c) is K_(p)=K_(c)(RT)^(Deltan) unit of K_(p)=(atm)^(Deltan), unit of K_(c)=(mol L^(-1))^(Deltan) Consider the two reaction: XeF_(6)(g)+H_(2)O(g) hArr XeO_(3)F_(4)(g)+2HF(g), K_(1) XeO_(4)(g)+XeF_(6)(g) hArr XeOF_(4)(g)+XeO_(3)F_(2)(g), K_(2) Then the equilibrium constant for the following reaction XeO_(4)(g)+2HF(g) hArr XeO_(3)F_(2)(g) is given by:
Answer» `K_(1)//K_(2)^(2)` `(K_(1)//K_(2))^(1//2)` `K_(1)^(2)//K_(2)^(3)` `K_(2)//K_(1)` SOLUTION :`K=K_(2)/K_(1)`