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The relation between `mu` and `H` for a specimen of iron is `mu=[(0.4)/(H)+12xx10^(-4)]henry//metre`. The value of `H` which produces flux density of `1` tesla will beA. `250A//m`B. `500A//m`C. `750A//m`D. `10^(3)A//m` |
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Answer» Correct Answer - B `B = muH` `B = [(0.4)/(H) + 12x10^(-4)]H` |
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