The relation between position and time f for a particle , performingone dimensional motion is as under : t = sqrt(x) +3 Here x is in metre and t is in second . (1) Find the displacementof the particle when its velocitybecomes zero . (2) Ifa constant force acts on the particle , find the workdone in first 6 second .

The relation between position and time f for a particle , performingon

1.	The relation between position and time f for a particle , performingone dimensional motion is as under : t = sqrt(x) +3 Here x is in metre and t is in second . (1) Find the displacementof the particle when its velocitybecomes zero . (2) Ifa constant force acts on the particle , find the workdone in first 6 second .
Answer» Solution :`t = sqrt(x)+3` ` :. x =(t-3)^(2)` Now `v=(DX)/(dt) =2(t-3)` At time t = 0 , velocity `v_(1)=-6 m//s ` At time t=6 velocity `v_(2) = 6 m//s ` ` :. DeltaK = 1/2 mv_(2)^(2) - 1/2 mv_(1)^(2)` ` = 1/2 m [ (6)^(2)-(-6)^(2)] = 1/2 m [36 -36] ` ` :. DeltaK = 0 "" :. "Work W = 0 "`