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The relation between pressure exerted by an ideal gas (p_("ideal")) and observed pressure (p_("real")) is given by the equationP_("ideal")=P_("real")+(an^(2))/(V^(2))(i) If pressure is taken in Nm^(-2), number of moles in mol and volume in m^(3), Calculate the unit of .a..(ii) What will be the unit of .a. when pressure is in atmosphere and volume in dm^(3) ? |
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Answer» Solution :Given that, `P_("ideal")=P_("real")+(an^(2))/(V^(2))` (i) a = If units of `p = NM^(2)`, units of `V=m^(3)`, units of n = mol then, units of `a =(Nm^(-2)(m^(3))^(2))/((mol)^(2))=Nm^(4)mol^(-2)` (II) If units of p = atm, units of `V = DM^(3)`, units of n = mol then, units of `a = (PV^(2))/(n^(2))=(atm.(dm^(3))^(2))/((mol)^(2))` = atm `dm^(6)mol^(-2)` |
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