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The relation between U,P and V for an ideal gas is U=2+3PV . What is the atomicity of gas. |
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Answer» Solution :For an ADIABATIC process `dQ=0=dU+dW or 0=dU+PDV" _____"(1)` From the given equation `dU=3(PdV+VdP)` `:. 0=3(PdV+VdP)+PdV ("from "(1)) or 4P (dV)+3V(dP)=0 or 4[(dV)/V]=-3[(dP)/P]` On integrating, we get In `(V^(4))+ In (P^(3))="constant "(or) PV^(4//3)=constant` i.e., `gamma=4/3` i.e., GAS is polyatomic. |
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