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The relationship between de Broglie’s wavelength and momentum is A) λ = h + p B) λ = h/pC) λ = h x p2 D) λ = p/h |
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Answer» The correct option is (B) λ = h/p. The relationship between momentum and wavelength for matter waves is given by p = h/λ, and the relationship energy and frequency is E = hf. The wavelength λ = h/p is called the de Broglie wavelength, and the relations λ = h/p and f = E/h are called the de Broglie relations. |
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