InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The relationship between kinetic energy (K) and potential energy (U) of electron moving in a orbit arund the nucleus isA. `U=-K`B. `U=-2K`C. `U=-3K`D. `U=-(1)/(2)K` |
|
Answer» Correct Answer - B Kinetic energy, `K=(1)/(2)mv^2=(e^2)/(8piepsilon_0r)` and P.E.,`U=-(e^2)/(4piepsilon_0r)` or `K=(1)/(2)mv^2=(e^2)/(8piepsilon_0r)rArrU=-2K`. |
|